Respuesta :
The value of [tex]x=3+\sqrt{5}[/tex] make the quadratic equation true.
Quadratic equation :
Given equation is,
[tex](x-3)^{2}=5[/tex]
We have to solve above quadratic equation.
Expand above equation first,
[tex](x-3)^{2}=5\\\\x^{2} +9-6x=5\\\\x^{2} -6x+4=0\\\\x=\frac{6\pm \sqrt{36-16} }{2} \\\\x=3\pm\sqrt{5}[/tex]
Thus, the value of [tex]x=3+\sqrt{5}[/tex] make the quadratic equation true.
Learn more about the quadratic equation here:
https://brainly.com/question/1214333