Question

A student titrates 0.2087 g of an unknown diprotic acid with 0.1224 M sodium hydroxide. It takes 32.47 mL of the NaOH solution to reach the endpoint. How many moles of NaOH are used in the titration

Answer 1

Given :

A student titrates 0.2087 g of an unknown diprotic acid with 0.1224 M sodium hydroxide.

It takes 32.47 mL of the NaOH solution to reach the endpoint.

To Find :

How many moles of NaOH are used in the titration.

Solution :

Number of moles( n ) is given by :

n = Molarity × Volume( in liters )

n = $0.1224 \times \dfrac{32.47}{1000}\ moles$

n = 0.00397 moles.

Therefore, moles of NaOH are used in the titration is $3.97\times 10^{-3} \ moles$.

Answer 2

The number of moles  of NaOH are used in the titration is $3.97 \times 10^{-3}$ moles.

• The calculation is as follows;

The number of moles should be

$= molarity \times volume\\\\= 0.1224 \times \frac{32.47}{1000}$

= 0.00397 moles.

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