Answer:
the magnitude of the constant acceleration is 6.98 m/s²
Explanation:
Given;
distance traveled at a constant velocity, d = 130 m
time of motion, t = 4.9 s
The constant velocity is calculated as;
[tex]v = \frac{d}{t} \\\\v = \frac{130}{4.9} \\\\v = 26.53 \ m/s[/tex]
The car comes to a stop in 3.8 s.
When the car comes to a complete stop, the final velocity of the car will be zero.
the constant acceleration is calculated as;
v = u + at
0 = u + at
at = -u
a = -u/t
a = (-26.53) / (3.8)
a = -6.98 m/s²
Therefore, the magnitude of the constant acceleration is 6.98 m/s²
