Answer
The multiplicative rate of change that should be in Hal’s function = 49/50=0.98
=9.8×10⁻¹

Explanation
The investment of $10,000 decreases by 2% every year. So the following year is usually (100 - 2)=98% of the previous year. This is a geometric progression.
In this case the first term = 10000
The second term = 98% × 10000 = 9800.
The common ratio = 9800/10000=49/50
The multiplicative rate of change that should be in Hal’s function = 49/50=0.98.
The equation of the exponential rate would be;
10,000ₓ0.98ⁿ.
where n is the number years.

Answer The multiplicative rate of change that should be in Hals function 4950098 9810 Explanation The investment of 10000 decreases by 2 every year So the follo class=
Answer The multiplicative rate of change that should be in Hals function 4950098 9810 Explanation The investment of 10000 decreases by 2 every year So the follo class=

Respuesta :

Answer:

Answer:

1). Option (A)

2). Option (A)

Step-by-step explanation:

1). A worker bee has the mass = 0.00011 kg

  In scientific notation we can convert the mass of bee as,

  0.00011 =

                =

  Since 1.1 ≈ 1,

  Therefore, 1.1 × 10⁻⁴ ≈ 1 × 10⁻⁴ kg

  Option (A) is the answer.

2). An African elephant has a mass = 8139 kg

   In scientific notation,

   8139 = 8.139 × 10³

   Since, 8.139 ≈ 8

   Therefore, 8139 kg = 8.139 × 10³ kg

   Option (A) is the answer.

Step-by-step explanation:

Hope this helps! ;)

Answer:

The investment of $10,000 decreases by 2% every year. So the following year is usually (100 - 2)=98% of the previous year. This is a geometric progression.

In this case the first term = 10000

The second term = 98% × 10000 = 9800.

The common ratio = 9800/10000=49/50

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98.

The equation of the exponential rate would be;

10,000ₓ0.98ⁿ.

where n is the number years.

Step-by-step explanation:

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