Answer:
The correct option is d.
Step-by-step explanation:
The average rate of change of a function between two points is defined as
[tex]m=\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]
If during a time period the average rate of change is zero, then
[tex]0=\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]
[tex]0=f(x_2)-f(x_1)[/tex]
It means the value of the function is same for both the points.
From the given table it is clear that the weight is same for 5th and 6th week.
[tex]m=\frac{f(6)-f(5)}{6-5}[/tex]
[tex]m=\frac{137-137}{1}[/tex]
[tex]m=0[/tex]
So, the average rate of change zero from week 5 to week 6.
Therefore the correct option is d.