Question

1. Find the distance between two
points with coordinates (-2.6, -4.7)
and (-2.6, 4.7).
A) 2.6 units
B) 5.2 units
C) 7.3 units
D) 9.4 units
PLSS help me I’m slow

Answer 1

Answer:

$\mathrm{D)\:}9.4\: \mathrm{units}$

Step-by-step explanation:

Solution 1:

Notice the $x$ coordinate of both points are equal, meaning both points are on a vertical line. The distance between two points on a vertical line is the absolute difference of their y-coordinates. The absolute difference between $4.7$ and $-4.7$ is $|4.7-4.7|=\fbox{ 9.4 }$.

Solution 2:

The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Plugging in given values, we have:

$d=\sqrt{(-2.6-(-2.6))^2+(4.7-(-4.7))^2},\\d=\fbox{ 9.4 }$.