Question

Find the volume, in Liters, of 2.5 x 1024 molecules of chlorine gas at STP.

Answer 1

Answer:

V = 93.0 L

Explanation:

Hello!

In this case, when computing the PVT properties for an ideal gas, we need to use the following equation:

$PV=nRT$

In such a way, for 2.5 x 10²⁴ molecules of chlorine at STP (273.15 K and 1.00 atm) we first need the moles based on the Avogadro's number:

$n = 2.5x10^{24}molec*\frac{1mol}{6.022x10^{23}molec} = 4.15mol$

Now, we solve for volume on the ideal gas equation to obtain:

$V=\frac{nRT}{P}$

So we plug in and get:

$V=\frac{4.15mol**0.08206\frac{atm*L}{mol*K}*273.15K}{1.00atm}\\\\V=93.0L$

Best regards!