Question

Question 6
A machine is used to fill bags with a popular brand of trail mix. The machine is calibrated so the distribution of the weights of the bags of trail mix is normal,
with mean 240 grams and standard deviation 3 grams. Of the following, which is the least weight of a bag in the top 5 percent of the distribution?

Answer 1

Answer:

D. 246 grams

Step-by-step explanation:

invnorm(.95, 240, 3) is around 244 and the question is asking for the least weight of a bag in the top 95%, so the smallest number within

a. 234

b. 240

c. 243

d. 246

e. 248

is d.

Answer 2

The distribution of the mix follows inverse normal distribution

The least weight of a bag in the top 5% is 246 grams

The given parameters are:

$\mathbf{\mu = 240}$ ---- population mean

$\mathbf{\sigma = 3}$ ---- population standard deviation

To get the least weight of a bag in the top 5%, we make use of inverse normal distribution.

So, we have:

$\mathbf{Least = invNorm(p,[\mu,\sigma])}$

Being in the top 5% means that:

p = 1 - 5%

p = 1 - 0.05

p = 0.95

So, we have:

$\mathbf{Least = invNorm(0.95,240,3)}$

From the inverse normal calculator, we have

$\mathbf{Least = 246}$

Hence, the least weight is 246 grams

Read more about inverse normal distributions at:

https://brainly.com/question/15798227