Question

Find the x- and y-intercepts for the following equation.
-4 x + 3 y = 9
x-intercept
a =


y-intercept
b =

Answer 1

to find the x int, sub in 0 for y and solve for x
-4x + 3y = 9
-4x + 3(0) = 9
-4x = 9
x = -9/4.....so ur x int is -9/4 or (-9/4,0)

to find the y int, sub in 0 for x and solve for y
-4x + 3y = 9
-4(0) + 3y = 9
3y = 9
y = 9/3
y = 3...so ur y int is 3 or (0,3)

Answer 2

Answer:

x-intercept (a): $x = -\frac{9}{4}$

y-intercept (b): $y =3$

Step-by-step explanation:

-4 x + 3 y = 9

-4x + 3y = 9

-4x + 3(0) = 9

-4x + 0 = 9

-4x = 9

/-4   /-4

$x = -\frac{9}{4}$

-4(0) + 3y = 9

0 + 3y = 9

3y = 9

/3   /3

$y =3$

Hope that helps!