Question

HELP PLEASE In the following cross, assume simple dominance and independent assortment for each trait. What proportion of the progeny will be expected to phenotypically resemble the second parent?


AABB x Aabb

1. 1/4

2. 1/8

3. 3/4

4. 3/8

Answer 1

Answer:

0

Explanation:

This question involves two genes; A and B. According to the question, two parents are crossed as follows: AABB × Aabb. The parents will produce the following gametes:

AABB- AB, AB, AB, AB

Aabb - Ab, Ab, ab, ab

Using these gametes in a punnet square (see attached image), the offsprings in the following proportion will be produced:

AABb = 4/16 = 1/4

AaBb = 4/16 = 1/4

Therefore, none (0) of the offsprings will resemble the phenotype of the second parent (Aabb).