This is what someone else answered when someone else asked it. I can't explain it better than this.
So five sibbllings ages are repressented as
a,b,c,d,e
let's have a as youngest and e as oldest in that order
total ages are 195 so
a+b+c+d+e=195
oldest is 13 older thatn youngest
e=13+a
middle child anne (c) is 5 years younger than josie who is an unknow position, we know that she could be d or e or oldest or second oldest
the other 2 are 6 years appart
b and d ar e 6 years appart or b and e are 6 years apart? or is josie the oldest, or second oldest?
second oldes is 42 so
d=42
2 scenarios
if josie is oldest, then see AAAA and if josie is second oldest then see BBBB
AAAA
josie is 13 years older than mark
e=13+a
anne is 5 less than josie
c=e-5
the other 2 are 6 years apart
b+6=d
d=42
subsitute and get
b=36
add and get
78+a+c+e=195
a+c+e=117
e-13+e-5+e=117
3e-18=117
add 18 to both sides
3e=135
divided both sides by 3
e=45
subsitute
a=32
b=36
c=40
d=42
e=45
BBBB
oldest is 13 older than youngest
e=13+a
middle is 5 younger than josie (d)
c=d-5
the other 2 are 6 apart
b=e-6
d=42
subsitute
c=37
subsitute
a+b+37+42+e=195
a+b+e+79=195
subtract 79 from both sides
a+b+e=116
subsitute
e-13+e-6+e=116
3e-19=116
add 19 to both sides
3e=135
divide both sides by 3
e=45
subsitute
45-6=39=b
45-13=32=a
c=42-5=37
this is wrong because b cannot be older than c so therefor AAA si the correct answer
THE ANSWER IS
Josie is the oldest=45
Unknown is second oldest=42
Anne is middle=40
Unknown2 is second youngest=36
Mark is the youngest=32
