Respuesta :
Answer is: 20.0g H - 20.0 moles; 0.50 g Na - 0.022 moles; 2.0 x 102 mg H2O - 0.011 moles.
1) m(H) = 20.0 g; mass of hydrogen.
n(H) = m(H) ÷ M(H).
n(H) = 20 g ÷ 1 g/mol.
n(H) = 20.0 mol; amount of hydrogen.
2) m(Na) = 0.50 g; mass of sodium.
n(Na) = m(Na) ÷ M(Na).
n(Na) = 0.5 g ÷ 22.98 g/mol.
n(Na) = 0.022 mol; amount of sodium.
3) m(H₂O) = 200 mg ÷ 1000 mg/g.
m(H₂O) = 0.20 g; mass of water.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 0.2 g ÷ 18 g/mol.
n(H₂O) = 0.011 mol; amount of water.
Answer:
1. 10.0 g H
3
0.011 moles
2. 0.25 g Na
1
9.92 moles
3. 1.0 x 102 mg H2O
2
0.0056 moles
Explanation: