Question

2. The side of a square exceeds the side of
another square by 5 cm. The difference of
their areas is 325 sq. cm. Find the sides of
each square.​

Answer 1

Answer:

$x=30cm$

$y=30+5=>35cm$

Step-by-step explanation:

From the question we are told that

Sides difference $\triangle x= 5cm$

Area difference  $\triangle a=326sq.cm$

Let first square be A

Let second square be B

Generally the area of a square is mathematically given by

Area of a square$A=x*x=x^2$

Area of a square$B=(x+5)^2=x^2+25+10x$

$Area \A - Area\ B =325$

Therefore from the equations above

$x^2+25x+10-x^2=325$

$10x=325-25$

$x=300/10$

$x=30cm$

Therefore

Side of the first square

$x=30cm$

Side of the second square.

$y=>30+5=35cm$

Check answer

$35^2-30^2=325$