[tex]y = 4 {(x - 6)}^{2} + 3[/tex]
[tex]y = a {(x - h)}^{2} + k[/tex]
where a-term determines how wide/narrow/upward or downward of the graph.
h-term determines the changes of graph for x-axis
k-term determines the changes of graph for y-axis.
The vertex of parabola is at (h,k).
[tex]y = 4 {(x - ( + 6)})^{2} + ( + 3)[/tex]
Therefore, h = 6 and k = 3.
[tex] \large \boxed{(6,3)}[/tex]