Question

What is the frequency of a photon with an energy of 3.38 x 10-19 J?
A. 6.71 x 1014 Hz
B. 5.10 1014 Hz
C. 1.96 1014 Hz
D. 4.47 1014 Hz

Answer 1

Answer:1.96*10^14 Hz

Explanation: energy = frequency*Planck constant

3.38*10^-19 J= frequency Hz*6.62607015*10^-34 Jsec

freq Hz = 3.38*10^-19/6.62607015*10^-34 = about 2*10^14

Answer 2

Answer:5.10 x 1014

Explanation: