Question

A bicycle rim has a diameter of 0.65 m and a moment of inertia, measured about its center, of 0.21 kg⋅m2What is the mass of the rim?

Answer 1

Answer:

m = 1.99 kg = 2 kg

Explanation:

The moment of inertia of a bicycle rim about it's center is given by the following formula:

$I = mr^{2}$

where,

I = Moment of Inertia of the Bicycle Rim = 0.21 kg.m²

r = Radius of the Bicycle Rim = Diameter of the Bicycle Rim/2

r = 0.65 m/2 = 0.325 m

m = Mass of the Bicycle Rim = ?

Therefore,

$0.21\ kg.m^{2} = m(0.325\ m)^{2}\\m = \frac{0.21\ kg.m^{2}}{(0.325\ m)^{2}}$

m = 1.99 kg = 2 kg

Answer 2

The mass of the rim is 1.99 kg. Mass is a numerical measurement of inertia, which is an entire amount of all matter.

What is mass?

Mass is a numerical measure of inertia, which is a basic feature of all matter. It is, in effect, a body of matter's resistance to a change in speed or position caused by the application of a force.

The given data in the problem is;

I is the Moment of Inertia of the bicycle Rim = 0.21 kg.m²

r is radius of the bicycle Rim = d/2= 0.65/2= 0.325

m is the mass of the bicycle Rim=?

The moment of inertia of a bicycle rim about its center will be;

$\rm I= mr^2 \\\\ \rm m= \frac{I}{r^2} \\\\ \rm m= \frac{0.21}{(0.325)^2} \\\\ \rm m=1.99\ Kg$

Hence the mass of the rim is 1.99 kg.

To learn more about the mass refer to the link;

https://brainly.com/question/13073862