Pls help me with this question.
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Answer:
The slope for this equation is [tex]\frac{1}{7}[/tex].
Step-by-step explanation:
x y
point 1: -4 -3
point 2: 3 -2
slope: [tex]\frac{1}{7}[/tex]
To solve for slope here is an equation, to help: [tex]\frac{y^2-y^1}{x^2-x^1}[/tex]
[tex]\frac{y^2-y^1}{x^2-x^1} \\\\\frac{-2-(-3)}{3-(-4)} \\\\= \frac{1}{7} \\[/tex]