Question

Two skaters stand facing each other. The first skater has a mass of 71 kg and the second has a mass of 65 kg. They push against each other and the 71 kg skater acquires a speed of 3.4 m/s. How fast is the 65 kg skater moving

Answer 1

Answer:

4m/s approx

Explanation:

Step one

Given data

m1=71kg

m2=65kg

v1=3.4m/s

v2=??

We are required to find the Velocity of the second person

By applying the conservation of momentum principles

P=mv

m1v1=m2v2

Substitute

71*3.4=61*v2

241.4=61v2

Divide both sides by 61

v2=3.95m/s

v2=4m/s approx