A graduated cylinder contains 10.00 mL water. A 14.74 g piece of aluminum is added to the water, and the volume rises to 15.46 mL. What is the density of the aluminum in g/mL

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Answer:

2.67 g/mL

Explanation:

Initial Volume of water = 10.0 mL

Final Volume pf water = 15.46 mL

Mass = 14.74g

Density = Mass / Volume of aluminium

Volume of aluminium = Final Volume of water - Initial Volume of water = 15.46 - 10 = 5.46mL

Density = 14.74 / 5.46 = 2.67 g/mL

The density of aluminum has been 2.699 g/ml.

The density has been defined as the mass per unit volume. The addition of aluminum to the water results in the rise in the volume of the water.

The rise or change in the volume of water has been based on the volume of the aluminum.

The initial volume of water = 10 ml

The final volume of water = 15.46 ml

The volume of aluminum = Final volume - Initial volume

The volume of aluminum = 15.46 - 10 ml

The volume of aluminum = 5.46 ml

The density can be expressed as;

Density = [tex]\rm \dfrac{mass}{volume}[/tex]

The given mass of the aluminum = 14.74 g.

The density of aluminum = [tex]\rm \dfrac{14.74}{5.46}[/tex]

The density of aluminum = 2.699 g/ml.

The density of aluminum has been 2.699 g/ml.

For more information about density, refer to the link;

https://brainly.com/question/18320053

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