Question

A student drove to campus from her home and noted that the odometer reading of her car increased by 12 km. The trip took 18 minutes. If the straight line distance from her home to the university is 10.3 km in a direction 25 degrees south of east, what was the magnitude of her average velocity in km/hr

Answer 1

Answer:

$34.33\ \text{km/h}$

Explanation:

t = Time taken in her journey = 18 minutes =$\dfrac{18}{60}\ \text{hours}$

s = Displacement of the student = $10.3\ \text{km}$

Average velocity is given by

$v=\dfrac{\text{Displacement}}{\text{Time taken}}\\\Rightarrow v=\dfrac{s}{t}\\\Rightarrow v=\dfrac{10.3}{\dfrac{18}{60}}\\\Rightarrow v=34.33\ \text{km/h}$

The magnitude of the student's average velocity is $34.33\ \text{km/h}$.