Question

Help me with this question

Answer 1

Answer:

The correct option is: x > z

Hence, option D is correct.

Step-by-step explanation:

Given

• $\frac{3y+1}{2}=5$

• $\:\frac{4x}{3}=8$

• $\frac{z}{3}+\frac{z}{4}=2$

solving

$\frac{3y+1}{2}=5$

Multiply both sides by 2

$\frac{2\left(3y+1\right)}{2}=5\cdot \:2$

Simplify

$3y+1=10$

Subtract 1 from both sides

$3y+1-1=10-1$

Simplify

$3y=9$

Divide both sides by 3

$\frac{3y}{3}=\frac{9}{3}$

Simplify

$y=3$

also solving

$\:\frac{4x}{3}=8$

Multiply both sides by 3

$\frac{3\cdot \:4x}{3}=8\cdot \:3$

$4x=24$

Divide both sides by 4

$\frac{4x}{4}=\frac{24}{4}$

Simplify

$x=6$

also solving

$\frac{z}{3}+\frac{z}{4}=2$

Multiply by L.C.M

$\frac{z}{3}\cdot \:12+\frac{z}{4}\cdot \:12=2\cdot \:12$

Simplify

$4z+3z=24$

$7z=24$

Divide both sides by 7

$\frac{7z}{7}=\frac{24}{7}$

Simplify

$z=\frac{24}{7}$

$z=3.4$

Thus,

$y=3$

$x=6$

$z=3.4$

so

x > z

Therefore, the correct option is: x > z

Hence, option D is correct.