Question

Calculate the minimum frequency of ultrasound that will allow you to see details as small as 0.802 mm in human tissue. (Assume the speed of sound through human tissue is 1540 m/s.)

Answer 1

Answer:

the minimum frequency of ultrasound that will allow you to see the details is 1.92 x 10⁶ Hz.

Explanation:

Given;

wavelength, λ = 0.802 mm = 0.802 x 10⁻³ m

speed of sound in human tissue, v = 1540 m/s

The minimum frequency of ultrasound that will allow you to see the details is calculated as;

$f = \frac{v}{\lambda} \\\\f = \frac{1540}{0.802 \times 10^{-3}} \\\\f = 1.92 \ \times \ 10^6 \ Hz$

Therefore, the minimum frequency of ultrasound that will allow you to see the details is 1.92 x 10⁶ Hz.