Answer and Explanation:
The computation is shown below:
Given that
sample size n = 12
[tex]\sum X[/tex] = 22 + 21 + 16 + 18 + 15 + 23 + 17 + 24 + 20 + 19 + 22 + 11
= 228
Now
sample mean M is
[tex]= \sum X \div n[/tex]
= 228 ÷ 12
= 19
In the case when the each score would be divided by 2.5 so the size of the sample would remains the same But [tex]\sum X[/tex] and M would be
[tex]\sum X \div 2.5 \\\\M \div 2.5[/tex]
Now
New n = 12
[tex]New \sum X = Old \sum X \div 2.5[/tex]
= 228 ÷ 2.5
= 91.2
New Mean = Old mean ÷ 2.5
= 19 ÷ 2.5
= 7.6