Question

A chemist dissolves 613 mg of pure perchloric acid in enough water to make up 360 mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places.

Answer 1

Answer:

pH = 1.771

Explanation:

given data

weight = 613 mg

volume of solution = 360 mL

solution

we get here first molarity that is

molarity = $\frac{weight}{molecular \ weight} \times \frac{1000}{volume \ of\ solution}$       .................1

put here value

molarity = $\frac{613}{100.46} \times \frac{1000}{360}$

molarity = 0.01694 M

and

pH = -log[0.01694]

pH = 1.771