What is the angle of rotation from figure D to figure D’? Assume that the center of rotation is the origin.

Answer:
Angle of rotation is 90°.
Step-by-step explanation:
In the given figure point D is rotated about the origin and we get a new point D'
We join D and D' with origin by two lines forming oD and oD'
Now we get slopes of oD as [tex]m_{1}[/tex] and oD' as [tex]m_{2}[/tex]
Point D and D'are (-1.5, 3.5) and (3.5, 1.5) and origin as (0,0)
[tex]m_{1}[/tex] = [tex]\frac{(3.5-0)}{(-1.5-0)}=\frac{-3.5}{7.5}[/tex]
= -[tex]\frac{7}{3}[/tex]
[tex]m_{2}[/tex] = [tex]\frac{(1.5-0)}{(3.5-0)}=\frac{1.5}{7.5}[/tex]
= [tex]\frac{3}{7}[/tex]
Now [tex]m_{1}[/tex] × [tex]m_{2}[/tex] = [tex](\frac{-7}{3})(\frac{3}{7})[/tex]
= - [tex](\frac{7*3}{3*7})=(-1)[/tex]
Therefore, both the lines oD and oD' are perpendicular to each other.
Angle of rotation is 90°.