Question

A runner goes 88 m in 9.2 seconds what was his acceleration

Answer 1

Answer:

2.1m/s²

Explanation:

Given parameters:

Distance  = 88m

Time taken  = 9.2s

Unknown:

Acceleration = ?

Solution:

To solve this problem, we use the kinematics equation below;

        S  = ut  +   $\frac{1}{2}$ at²  

S is the distance

u is the initial velocity  = 0m/s

t is the time

a is the acceleration

         88  = (0 x 9.2) +   $\frac{1}{2}$ x a x 9.2²

          88 = 42.32a

           a  = 2.1m/s²