Answer:
n=28,m=6
Step-by-step explanation:
Rearrange to give 4704 = m * n^2
Express 4704 in its prime factorisation:
2^5 * 3^1 * 7^2
We know that n must be as large as possible and, because it is squared, be the even numbers.
We get n^2 = 2^4 * 7^2 so n = 2^2*7 = 28
m is the leftovers
2^1*3 = 6
The values of m is 6 and n is 28, where m and n are whole numbers.
Prime Numbers is defined as a number have exactly two factors, that is 1 and the number itself. Prime Numbers are greater than 1 . For example, 5 has only 2 factors, 1 and 5 itself. So, it is a prime number.
Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.
+ Addition operation: Adds values on either side of the operator.
For example 12 + 2 = 14
- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.
for example 12 -2 = 10
* Multiplication operation: Multiplies values on either side of the operator
For example 12*2 = 24
Given that
4704/m = n²
4704 = m n²
where m and n are whole numbers
To determine the converted prime factorization form
4704 = 2⁵ × 3¹ × 7²
Given that n must be as large as it can be and that it must be an even number because it is squared.
We obtained n² = 2⁴ × 7²
So n = 2²× 7 = 28
The rest are m.
So, m = 2 × 3 = 6
Hence, the values of m is 6 and n is 28, where m and n are whole numbers.
Learn more about Arithmetic operations here:
https://brainly.com/question/25834626
#SPJ2
