Respuesta :
Answer:
The height of water in the cylindrical vase is 6.2 cm.
Step-by-step explanation:
Volume of water in the measuring jug = 310 [tex]cm^{3}[/tex].
The radius of the cylindrical vase = 4 cm
volume of cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h
But,
volume of water in the jug = volume of water in the vase = 310 [tex]cm^{3}[/tex]
So that,
310 = [tex]\frac{22}{7}[/tex] x [tex](4)^{2}[/tex] x h
= [tex]\frac{22}{7}[/tex] x 16 x h
310 x 7 = 22 x 16 h
2170 = 352h
h = [tex]\frac{2170}{352}[/tex]
= 6.163
h = 6.2 cm
The height of water in the cylindrical vase is 6.2 cm.
The height of water of the jug in cm is; 6.2 cm
- We are told that the jug was filled with 310 cm of water. This amount is the volume(V)
We are given radius(r) = 4cm
- Now, a jug is usually a cylindrical shape and the formula for volume is;
V = πr²h
Thus;
310 = π × 4² × h
h = 310/(16π)
h = 6.167 cm
Approximating, we have; h = 6.2 cm
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