Question

Line q goes through points (-3, 3) and (-5, -3)at what point does line q cross the y-axis?

Answer 1

Answer: At point (0,12)  line q cross the y-axis.

Step-by-step explanation:

Equation of a line passing through (a,b) and (c,d) :

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Given: Line q goes through points (-3, 3) and (-5, -3).

Equation of line q:

$(y-3)=\dfrac{-3-3}{-5(-(-3)}(x-(-3))\\\\\Rightarrow\ (y-3)=\dfrac{-6}{-5+3}(x+3)\\\\\Rightarrow\ (y-3)=\dfrac{-6}{-2}(x+3)\\\\\Rightarrow\ y-3=3(x+3)$

When line crosses y-axis , x=0 .

So,

$y-3=3(3)\\\\\Rightarrow\ y-3=9\\\\\Rightarrow\ y=9+3\\\\\Rightarrow\ y=12$

Hence, At point (0,12)  line q cross the y-axis.