Question

Suppose that the total number attendance A (in thousands) at NCAA women's basketball games is modeled by the polynomial function A(t) = -1.95t3 + 70.1t2 – 188t + 2150, from 2000 to 2018, where t is the number of years since 2000. Find the attendance for the year 2010.

Answer 1

Answer:

5,330

Step-by-step explanation:

Given

A(t) = -1.95t³ + 70.1t² – 188t + 2150

Where,

t = number of years since 2000

Find the attendance for the year 2010

t = 10 (2000 to 2010)

A(t) = -1.95t³ + 70.1t² – 188t + 2150

= -1.95*10³ + 70.1*10² - 188*10 + 2150

= -1.95*1000 + 70.1*100 - 1,880 + 2150

= -1,950 + 7,010 - 1,880 + 2,150

= 5,330

A = 5,330

The attendance for the year 2010 = 5,330

Answer 2

The attendance for the year 2010 is 5,330.

Given that,

• The polynomial function is $A(t) = -1.95t^3 + 70.1t^2 - 188t + 2150$.
• Here t be the no of years.
• From 2000 to 2010, the n be = 10 years.

Based on the above information, the calculation is as follows:

$A(t) = -1.95t^3 + 70.1t^2 - 188t + 2150\\\\ = -1.95t^3 + 70.1t^2 - 188t + 2150\\\\= -1.95 \times 10^3 + 70.1\times 10^2 - 188\times 10 + 2150\\\\= -1.95\times 1000 + 70.1\times 100 - 1,880 + 2150\\\\= -1,950 + 7,010 - 1,880 + 2,150$

= 5,330

Therefore, we can conclude that the attendance for the year 2010 is 5,330

Learn more: brainly.com/question/16115373