Question

1. A candy bowl in Blake's kitchen has 12 red candies, 15 blue candies, 6 green candies, 11 yellow candies and 16 orange candies. Blake randomly chooses one candy from the bowl without looking. What is the probability that he will choose a red, green or orange candy? Express your probability answer as a fraction, decimal and percent

Answer 1

Answer:

The probability that Blake will choose a red, green or orange candy $\frac{17}{30}$ or $0.57$ or $56.67\%$.

Step-by-step explanation:

Number of red candies $=12$.

Number of blue candies $=15$.

Number of green candies $=6$.

Number of yellow candies $=11$.

Number of orange candies $=16$.

Total number of candies $=12+15+6+11+16=60$.

Probability of an event $\textrm{E}$, $\textrm{P}(\textrm{E})=\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}$

Number of red, green or orange candies $=12+6+16=34$.

So, the probability that he will choose a red, green or orange candy $=\frac{34}{60} =\frac{17}{30}$ or $0.57$ or $56.67\%$.