Question

What is the equation of a line perpendicular to the line given by y = (3/7)x+ 9
and containing the point (-5, 11)?
O y = (-5X/7) + 4
O y = (-7X/5) + 4
O y = (7X/5) + 4
O y = (5x/7) + 4

Please help me
I need to finish this

Answer 1

Answer:

B) y = (-7X/5) + 4

Step-by-step explanation:

Recall two lines are perpendicular if their slopes are negative reciprocals (5/7 goes to -7/5).

Assuming in the form y = mx + b:

Solving for b:

-7/5(-5) + x = 11

(5's & negatives cancel out...)

7 + x = 11

x = 4

y = -7/5x + 4