Answer:
[tex]\mathbf{1 + log_3 ( 45x + 27y)}[/tex]
Step-by-step explanation:
Given that:
[tex]log_3 (135x + 81 y) \\ \\ = log_3 [ 3 (45x + 27y) ][/tex]
Since [tex]log (ab) = log \ a +log \ b[/tex]
Then
[tex]log_3 [ 3 (45x + 27y) ] = log_3 (3) + log_3 ( 45x + 27y)[/tex]
Since [tex]log_a (a) = 1[/tex]
Then
[tex]log_3 (3) + log_3 ( 45 + 27y) = 1 + log_3 ( 45x + 27y)[/tex]