Answer:
[tex]y = -\frac{3}{5}x+4[/tex]
Step-by-step explanation:
Given:
[tex](x_1,y_1) = (0,4)[/tex]
[tex](x_2,y_2) = (5,1)[/tex]
The attachment completes the question
From the attachment, the slope of the line was calculated as:
[tex]m = \frac{1-4}{0-5}[/tex]
This step is inaccurate because the slope of a line is calculated using
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
Which gives
[tex]m = \frac{1-4}{5-0}[/tex]
[tex]m = \frac{-3}{5}[/tex]
[tex]m = -\frac{3}{5}[/tex]
The line equation is then calculated using:
[tex]y -y_1 = m(x - x_1)[/tex]
Substitute values for m, x1 and y1
[tex]y - 4 = -\frac{3}{5}(x - 0)[/tex]
[tex]y - 4 = -\frac{3}{5}(x)[/tex]
Open bracket
[tex]y - 4 = -\frac{3}{5}x[/tex]
Make y the subject
[tex]y = -\frac{3}{5}x+4[/tex]
