Question

HJ


is extended through point J to point K, \text{m}\angle JHI = (x+12)^{\circ}m∠JHI=(x+12)


∘


, \text{m}\angle HIJ = (x-3)^{\circ}m∠HIJ=(x−3)


∘


, and \text{m}\angle IJK = (5x-6)^{\circ}m∠IJK=(5x−6)


∘


. Find \text{m}\angle IJK.m∠IJK.

Answer 1

Answer:

19 degrees

Step-by-step explanation:

From the question given

The interior angles are x+12 and x - 3

Exterior angle is <IJK = 5x-6

Using the rule that states that the sum of interior angle of a triangle is equal to the exterior

<JHI + <HIJ = <IJK

x+12 + x-3 = 5x - 6

2x+9 = 5x -6

2x - 5x = -6-9

-3x = -15

x = -15/-3

x = 5

Get <IJK

Recall that <IJK = 5x - 6

<IJK = 5(5) - 6

<IJK = 25-6

<IJK = 19 degrees

Hence the measure of <IJK is 19 degrees