Answer:
0.069 M
Explanation:
Equation of the reaction:
H₂SO₄(aq) + 2NaOH(aq) ⇒ Na₂SO₄(aq)+2H₂O(l)
From the equation above, 2 mole of NaOH is required to reach equivalent point with 1 mole of H₂SO₄.
n'CV = nC'V' ........................ Equation 1
Where n and n' = are number of moles of acid and base respectively, C and C' = are molarities of acid and base respectively, V and V' are volumes of acid and base respectively.
make C the subject of the equation
C = nC'V'/n'V.............................. Equation 2
Given: n = 1, n' = 2, C' = 0.11 M, V = 25 mL, V' = 31.43 mL
Substitute into equation 2
C = (1×0.11×31.43)/(25×2)
C = 0.069 M.
Hence the molarity of H₂SO₄ is 0.069 M
