Question

What is magnitude of the acceleration of a particle of mass and charge placed between the plates of a parallel plate capacitor of charge density

Answer 1

Answer:

a = Qo / E0m

Explanation:

Answer 2

The acceleration of a particle of mass m and charge q placed between the plates of a parallel plate capacitor is, $a=\frac{q*E}{m}$

Let us consider that mass and charge of particle is m and q.

and electric filed between plates of a parallel plate capacitor is E.

The force on a particle between plates of capacitor is given as,

                                 $F=q*E$

And also,            $F=m*a$

Where a is acceleration of particle.

From above equations,

                         $m*a=q*E\\\\a=\frac{q*E}{m}$

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