Answer:
16.1 days
Explanation:
Note: The full question is attached as picture below
Daily demand d = 520
Annual demand D = 520*250 = 130000
Setup cost S = $680
Production rate p = 875
Holding cost H = 0.25*25 = 6.25
Optimal order quantity Q
[tex]Q = \sqrt{2DS/H}[/tex] [tex]\sqrt{p / p -d}[/tex]
[tex]Q = \sqrt{(2*130000*680)/6.25} \sqrt{875/875-520}[/tex]
Q = 8350
Length of production run = Q/d
Length of production run = 8350/520
Length of production run = 16.05769230769231
Length of production run = 16.1 days