Answer:
1.0058 g/mL
Explanation:
Note: Specific gravity of a substance is same as the relative density.
R.D = Density of the substance/ Density of water.
R.D = D/D'................... Equation 1
Make D the subject of the equation
D = R.D×D'................. Equation 2
Where R.D = Specific gravity of acetic acid, D = density of acetic acid, D' = density of water.
At 60°C,
R.D = 1.023, D' = 0.9832 g/mL
Substitute into equation 2
D = (1.023×0.9832)
D = 1.0058 g/mL
Hence the density of acetic at 60°C is 1.0058 g/mL
