Answer:
[tex]x_1=12,\;\;\;x_2=-7[/tex]
Step-by-step explanation:
B be an augmented matrix of the given system is:
[tex]B=[A,b]=\left[\begin{matrix}2&4&-4\\5&7&11\end{matrix}\right] \\\text{multiply the 2nd row by}\; \frac{1}{2}[/tex]
[tex]\left[\begin{matrix}1&2&-2\\5&7&11\end{matrix}\right][/tex]
add -5 times the 1st row to the 2nd row
[tex]\left[\begin{matrix}1&2&-2\\0&-3&21\end{matrix}\right][/tex]
multiply the 2nd row by [tex]\frac{-1}{3}[/tex]
[tex]\left[\begin{matrix}1&2&-2\\0&1&-7\end{matrix}\right][/tex]
add -2 times the 2nd row to the 1st row
[tex]\left[\begin{matrix}1&0&12\\0&1&-7\end{matrix}\right][/tex]
Hence the given system reduces to
[tex]x_1=12,\;\;\;x_2=-7[/tex]
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