Answer:
2/3v m/s
Explanation:
Given that
Mass of ball 1 = m
Initial velocity u1 of ball 1 = v m/s
Mass of ball 2 = 3m
Initial velocity u2 of ball 2 = v/2 m/s
Final velocity v1 of ball 1 = v/4 m/s
Final velocity v2 of ball 2 = ?
To solve this question, we will be applying the law of conservation of momentum, which is mathematically given as
m1u1 + m2u2 = m1v1 + m2v2
If we substitute the given values directly, we have
m * v + 3m * v/2 = m * v/2 + 3m * v2
mv + 3mv/2 = mv/2 + 3m * v2, collecting like terms, we have
mv + 3mv/2 - mv/2 = 3m * v2
mv + 2mv/2 = 3m * v2
mv + mv = 3m * v2
2mv = 3m * v2, dividing both sides by 3m
v2 = 2mv/3m
v2 = 2/3v
Therefore, the final velocity v2 of ball 2 is 2/3v
