Answer is given below:
Step-by-step explanation:
given data
sample n = 1600
P = 34 %
p = 31 %
solution
The null and alternative hypothesis are
H0: p = 0.31
Ha: p > 0.31
Test statistics
z = [tex]\hat{p} - p \sqrt{p (1 - p)}{n}[/tex]
z = 0.34 - 0.31 [tex]\sqrt{( 0.31 \times 0.69 / 1600)}[/tex]
z = 2.59
This is test statistics value.
p-value = P( Z > z)
p-value = P( Z > 2.59)
p-value = 0.0048
Since p-value < 0.05
level, we have sufficient evidence to reject H03
We conclude at 0.05 level that we have enough evidence t support the claim.