Question

The Question A 1.80 x 10-2 kg block of metal has the following dimensions: 0.4981 inches by 0.531 inches, by 0.5839 inches. Determine the density of the block in g/mL. Using the provided list of metals and their respective densities, what is the metal's identity

Answer 1

Answer:

Zinc

Explanation:

m = Mass of block $1.8\times 10^{-2}\ \text{kg}=18\ \text{g}$

Dimension of block is 0.4981 inches by 0.531 inches, by 0.5839 inches

$1\ \text{inch}^3=16.3871\ \text{mL}$

Volume of block

$V=0.4981\times 0.531\times 0.5839\times 16.3871\ \text{mL}$

Density is given by

$\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{18}{0.4981\times 0.531\times 0.5839\times 16.3871}\\\Rightarrow \rho=7.112\ \text{g/mL}$

The density of the metal is $7.112\ \text{g/mL}$. The metal here is zinc.