Question

calculate the number of grams of nitrogen gas required to make 1.22 l of ammonia at stp

Answer 1

Molar mass N₂ = 28.0 g/mol

1 mole -------- 22.4 ( at STP)
? mole -------- 1.22 L

1.22 x 1 / 22.4 => 0.0544 moles

Therefore:

1 mole ------------- 28.0 g
0.0544 moles --- ??

0.0544 x 28.0 / 1 => 1.5232 g of N₂