Answer:
a.0.5984
b.0.2394
c.0
d.13.4
Step-by-step explanation:
We are given that
a=6.3,b=20.5
The pdf of uniform distribution
[tex]f(x)=\frac{1}{b-a}=\frac{1}{20.5-6.3}=0.0704[/tex],6.3<x<20.5
0, otherwise
Now,
a.
P(10.2<x<18.7)=[tex]\int_{10.2}^{18.7}f(x) dx[/tex]
[tex]=0.0704[x]^{18.7}_{10.2}[/tex]
[tex]P(10.2<x<18.7)=0.0704(18.7-10.2)=0.5984[/tex]
b.P(x>17.1)
[tex]P(x>17.1)=\int_{17.1}^{20.5}0.0704dx[/tex]
[tex]=0.0704(20.5-17.1)[/tex]
[tex]=0.2394[/tex]
c.P(x<6.3)=0
d.E[x]=[tex]\frac{a+b}{2}=\frac{6.3+20.5}{2}=13.4[/tex]