Question

which of the answers are correct? there is possibly more than one.

Answer 1

Answer:

$b_2 = \frac{2A}{h} -b_1$

Step-by-step explanation:

Given

$A = \frac{1}{2}h(b_1 + b_2)$

Required

Select equivalent expressions

Multiply through by 2

$2*A = 2*\frac{1}{2}h(b_1 + b_2)$

$2*A = h(b_1 + b_2)$

$2A = h(b_1 + b_2)$

Divide through by h

$\frac{2A}{h} = \frac{h(b_1 + b_2)}{h}$

$\frac{2A}{h} = b_1 + b_2$

Subtract b1 from both sides

$\frac{2A}{h} -b_1= -b_1 + b_1 + b_2$

$\frac{2A}{h} -b_1= b_2$

$b_2 = \frac{2A}{h} -b_1$

From the list of options, there is only one answer