Question

plz help I will give brainliest to the first person who is correct
Find all real numbers z for which the equation $(z-5)x^2 - zx + 5 = 0$ only has one real solution. If you find more than one, then list the values separated by commas.

Answer 1

the answer is 6

z=6

explanation :

Answer 2

So if we want to find all the z_s for the quadratic equation, then we must equal discriminant to zero. The formula of discriminant is b^2-4ac. In our case, b^2-4ac=z^2-4•5•(z-5)=0

Z^2-20•(z-5)=0
Z^2-20z+100=0
Discriminant=400-400=0
Square root from 0=0

Z=20+_zero=20
Z=20