Answer:
The equation in slope-intercept form is: [tex]\mathbf{y=4x+6}[/tex]
Step-by-step explanation:
The points (1, 10) and (0, 6) fall on a particular line. What is its equation in slope-intercept form?
The general equation in slope-intercept form is: [tex]y=mx+b[/tex] where m is slope and b is y-intercept.
We need to find slope and y-intercept
Finding Slope:
The slope of equation can be found using formula: [tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
We have: [tex]x_1=1, y_1=10, x_2=0, y_2=6[/tex]
Now, finding slope:
[tex]Slope=\frac{y_2-y_1}{x_2-x_1} \\Slope=\frac{6-10}{0-1}\\Slope=\frac{-4}{-1}\\Slope=4[/tex]
So, we get slope = 4
Now Finding y-intercept
y-intercept can be found using slope m=4 and point (1,10)
[tex]y=mx+b\\10=4(1)+b\\10=4+b\\b=10-4\\b=6[/tex]
So, we get y-intercept b = 6
Equation of line.
Equation of line having slope m = 4 and b = 6
[tex]y=mx+b\\y=4x+6[/tex]
So, the equation in slope-intercept form is: [tex]\mathbf{y=4x+6}[/tex]