Answer:
Volume in L = 0.50 L
Explanation:
Given data:
Molarity of solution = 0.1850 M
Mass of BaCl₂ = 19.30 g
Volume of solution = ?
Solution:
First of all we will calculate the number of moles of solute:
Number of moles = mass/molar mass
Molar mass of BaCl₂ = 208.23 g/mol
Number of moles = 19.30 g / 208.23 g/mol
Number of moles = 0.093 mol
Volume of solution:
Molarity = number of moles of solute / volume of solution in L
0.1850 M = 0.093 mol / Volume in L
Volume in L = 0.093 mol / 0.1850 M (M= mol/L)
Volume in L = 0.50 L
