Question

Find the slope of a line that passes through (-2,-3) and (1,1)
A.) 1/3
B.) 1
C.) 2

Answer 1

I hope this helps you




(-2,-3) x'= -2 y'= -3



(1,1) x"=1 y"=1


slope. (x'-x")= y'-y"



slope. (-2-1)=-3-1



slope. -3 = -4


slope = 4/3

Answer 2

Answer:  4\3

Step-by-step explanation: Equation of line passing through (x1,y1) and (x2,y2) is given by

            y-y1=$\frac{y2-y1}{x2-x1} (x-x1)$

      here x1=-2,y1=-3,x2=1 and y2=1

      ⇒ y+3=$\frac{1+3}{1+2} (x+2)$

      ⇒ y+3=4(x+2)\3

       ⇒ y=4x\3 - 1\3

slope of line y=mx+c is equal to m

so slope=4\3